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Description: 输入三个整数x,y,z，请把这三个数由小到大输出。
-Enter three integers x, y, z, Please take this three the number of small to large output.
Platform: |
Size: 1024 |
Author: dongdong |
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Description: to plot a pointer.[X Y Z] = XYZPLOTTER(XIN,YIN,ZIN) transforms lists XIN, YIN, ZIN which
Platform: |
Size: 2048 |
Author: sach |
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Description: Description
给定一个有N个矩阵的矩阵链A1A2A3...An，矩Ai的维数为pi-1*pi。我们都知道，使用朴素的矩阵乘法去乘两个维数分别为x,y和y,z的矩阵，所需要的乘法次数为x*y*z。矩阵链乘法问题就是如何对矩阵乘积加括号，使得它们的乘法次数达到最少。
Input
输入的第一行为一个正整数N(1<=N<=200)。表示矩阵的个数。
输入的第二行包含N+1个整数，分别表示pi(0<=i<=N)，其中每个pi在[1,200]范围内。
Output
输出一个整数表示最少要进行的乘法次数。
-Description Given a matrix N a matrix chain A1A2A3 ... An, moments Ai dimension of pi-1* pi. We all know that the use of simple matrix multiplication to multiply two dimensions, respectively x, y, and y, z matrix, the required number of multiplication x* y* z. Matrix-chain multiplication problem is how to add the product to the matrix in parentheses, allowing them to reach a minimum number of multiplication. Input input first acts of a positive integer N (1 < = N < = 200). Indicated that the number of matrices. Enter the second line contains N+1 integers, respectively, indicated that pi (0 < = i < = N), where each pi in [1,200] range. Output output, said at least one integer number multiplication to be carried out.
Platform: |
Size: 406528 |
Author: 王泽萌 |
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Description: 实现一个三维点(x,y,z)的Point类。包含一个构造函数，一个复制构造函数，一个把这个点变成负的函数negate( )，一个返回到(0,0,0)点的距离的函数norm( )和一个print( )函数。
（1）为类Point实现一个重载的赋值运算符。
（2）为类Point实现重载的流插入运算符。
（3）为类Point实现重载的比较关系运算符==和!=。
（4）为类Point实现重载的加法+和减法运算符-。
（5）实现一个重载的乘法运算符*来返回两个Point类对象的点积。
-To achieve a three-dimensional point (x, y, z) of the Point class. Contains a constructor, a copy constructor, this point becomes a negative function negate (), a return to the (0,0,0) of a function of the distance norm (), and a print () function. (1) class Point to achieve an overloaded assignment operator. (2) class Point to achieve overloaded stream insertion operator. (3) Comparison of class Point to achieve overloaded relational operators == and! =. (4) To achieve the overloaded class Point addition+ and subtraction operator-. (5) to achieve an overloaded multiplication operator* to return two Point class object of the dot product.
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Size: 5120 |
Author: zengzeng |
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Description: 一个用单精度浮点数库计算的经纬度转换XYZ坐标转换源程序，精度达到双精度浮点数的精度，在VC或borlandc下均可运行的程序.-float to generate double accuracy. transfer (Latitude,Longitude,Height) to (X,Y,Z)
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Size: 190464 |
Author: 南帝 |
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Description: 采集鼠标，键盘信息。可以跟随鼠标的移动，点击。用空间坐标表示x，y，z，键值表示表示鼠标状态-Capture the mouse, keyboard information. Can follow the mouse movement, click on. Using space coordinates x, y, z, indicated that the mouse key state
Platform: |
Size: 15360 |
Author: 李世蓂 |
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Description: (1)X,Y,Z是同维向量，绘制以X,Y,Z元素为x,y,z坐标
的三维曲线
(2)X,Y,Z是同维矩阵，则以X,Y,Z对应列元素为x,y,z
坐标分别绘制曲线，曲线的条数等于矩阵的列数。
(3)s，s1，s2的意义与二维情况相同。
-(1) X, Y, Z is a vector with dimension, drawn to X, Y, Z elements x, y, z coordinates of the three-dimensional curve (2) X, Y, Z is a matrix with dimension, 则以 X, Y, Z corresponds to the column elements x, y, z coordinates of the drawn curve, the curve is equal to the number of bars the number of columns matrix. (3) s, s1, s2 of the meaning and the same two-dimensional case.
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Size: 199680 |
Author: wgy |
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Description: 设在内存区域中有数组X和Y。X数组有X1，X2，…，X10；Y数组有Y1，Y2，…，Y10，编程序实现下面的计算：
Z1=X1－Y1，Z2=X2＋Y2，Z3=X3－Y3，Z4=X4＋Y4，Z5=X5＋Y5，Z6=X6－Y6，Z7=X7－Y7，Z8=X8＋Y8，Z9=X9－Y9，Z10=X10＋Y10。计算结果Z存放在数组Z中。
为了便于检查结果，设数组X的内容为db 22,11,22,11,11,22,22,11,22,11,0,0,0,0,0,0存放于ds：0的内存中，为了便于计算，把数组X中的数补足16个；数组Y存放于ds：16开始的16个内存中，内容为11,88,11,88,88,11,11,88,11,88,0,0,0,0,0,0，而数组Z存放于ds：32的内存空间中，且数组值初始化为0。
数组X、Y、Z都是连续存放的！-Memory regions are located in an array of X and Y. X arrays are X1, X2, ..., X10 Y array with Y1, Y2, ..., Y10, programmed to achieve the following calculation: Z1 = X1-Y1, Z2 = X2+ Y2, Z3 = X3-Y3, Z4 = X4+ Y4, Z5 = X5+ Y5, Z6 = X6-Y6, Z7 = X7-Y7, Z8 = X8+ Y8, Z9 = X9-Y9, Z10 = X10+ Y10. The results stored in an array Z in Z. In order to facilitate the inspection results, set the contents of the array X as db 22,11,22,11,11,22,22,11,22,11,0,0,0,0,0,0 stored in ds: 0 Memory , in order to facilitate the calculation, the number of array X in the complement of 16 array Y stored in the ds: 16 of 16 starting in memory, says 11,88,11,88,88,11,11,88,11, 88,0,0,0,0,0,0, and stored in the array Z ds: 32 of the memory space, and the array value is initialized to 0. Array X, Y, Z are continuous storage!
Platform: |
Size: 5120 |
Author: 杜宾 |
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Description: OpenGL制作的轮胎模型，将轮胎的运动分解到X、Y、Z三个平面，是学习OpenGL影子模型的非常好的素材，原创代码-OpenGL produced tire model, the movement will tire decomposed into X, Y, Z three planes, the shadow model for learning OpenGL very good material, original code
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Size: 2711552 |
Author: 张沛轩 |
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Description: This a simple program that outputs the result of possibility to construct a triangle with the given 3 positive real numbers x, y, z, as a side lengths of the triangle.
-This is a simple program that outputs the result of possibility to construct a triangle with the given 3 positive real numbers x, y, z, as a side lengths of the triangle.
Platform: |
Size: 509952 |
Author: AY |
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Description: This a simple program that outputs the minimum and the maximum values of the given 3 real numbers x, y, z.-This is a simple program that outputs the minimum and the maximum values of the given 3 real numbers x, y, z.
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Size: 507904 |
Author: AY |
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Description: 混沌工具function [x,y,z]=rossler(n,level,a,b,c,x0,y0,z0,h)-function [x,y,z]=rossler(n,level,a,b,c,x0,y0,z0,h)
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Size: 1024 |
Author: chemgze |
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Description: 汇编语言顺序程序设计 计算(x+(y*z-100))/w-The order of assembly language programming computing (x+ (y* z-100))/w
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Size: 1024 |
Author: 李昕 |
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Description: 有关矢量信号处理的基本仿真，得到声压功率谱，x,y.z各方向声强谱-Vector signal processing related to the basic simulation，underwater acoustic
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Size: 1024 |
Author: Kyouya Young |
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Description: 给出三维点云的X,Y,Z坐标，重构出三维图像，其中用到了三角网格法和规则化坐标法。-Given 3D point cloud X, Y, Z coordinates, three-dimensional reconstructed images, which uses a triangular coordinate grid method and rules of law.
Platform: |
Size: 1024 |
Author: rongwei |
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Description: 为了图像处理的需要，很想实现二维图像的三维显示，于是写了本代码，希望与此有兴趣的读者共享。图像的获取一是bmp图像文件，二是来自剪贴板。本代码在MFC中调用OpenGL库函数来实现二维图像的三维显示，图像的宽度、高度和象素的亮度分别为三维空间的x,z,y坐标。程序主要有初始化、绘图、资源释放和操作部分，这些功能在OGL_MFCView.cpp文件中实现。OpenGL库的初始化在该文件中的OnCreate，InitScene和DrawScene函数中实现，主要初始化OpenGL运行时的环境变量，三维物体的光照，材质等，由于介绍OpenGL库的初始化的文档很多，在这里我就不多说了，感兴趣的读者可以参考有关的文档。在DrawScene函数中调用全局函数GLDraw3DBMP完成绘图部分。-I need to image processing, image to realize the three-dimensional display, two-dimensional wrote this code, then hope and the interested readers. The image of a file, the second is BMP image is from the clipboard. This code in MFC OpenGL library function call to realize the three-dimensional display, two-dimensional image width, height and pixel luminance respectively, the three-dimensional space x, y, z coordinate. Program mainly initialization, drawing, resources and release, these functions in operation, CPP files OGL_MFCView. OpenGL library in this document initialization of the OnCreate, InitScene and DrawScene function, main initialization OpenGL environment variables, the operation of the 3d object, etc, due to the light qualitative introduced OpenGL library initialization document in many, I am not here to say, interested readers can consult the relevant documents. In DrawScene function calls GLDraw3DBMP global function complete drawing parts.
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Size: 106496 |
Author: tom |
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Description: 使用VTk实现三维重建和虚拟切割，课在x,y,z三个方向观察切片-Three-dimensional reconstruction using VTk and virtual cutting
Platform: |
Size: 9985024 |
Author: 王旭 |
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Description: 经典Ｃ源程序100例 如题目：输入某年某月某日，判断这一天是这一年的第几天？
题目：输入三个整数x,y,z，请把这三个数由小到大输出。-Classic C source of 100 cases as subject: Enter One day a certain period to determine the day of the year, the first few days? Title: Enter three integers x, y, z, please put the number of small to large output of the three.
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Size: 18432 |
Author: 回强 |
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Description: 两个乒乓球队进行比赛，各出三人。甲队为a,b,c三人，乙队为x,y,z三人。已抽签决定
比赛名单。有人向队员打听比赛的名单。a说他不和x比，c说他不和x,z比，请编程序找出
三队赛手的名单。
-Two table tennis team to compete, each offering three. A team to a, b, c three-, B team for the x, y, z three. Already draw lots for the list. Competition was to find out the list of players. a said he did not and the x ratio, c said he did not, and x, z ratio, please programmed to identify a list of three teams racing.
Platform: |
Size: 2048 |
Author: yanyan |
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Description: 两个乒乓球队进行比赛，各出三人。甲队为a,b,c三人，乙队为x,y,z三人。已抽签决定 比赛名单。有人向队员打听比赛的名单。a说他不和x比，c说他不和x,z比，请编程序找出三队赛手的名单。-Two table tennis team to compete, each offering three. A team to a, b, c three-, B team for the x, y, z three. Has beendetermined by lotMatch list. Competition was to find out the list of players. a said he did not and the x ratio, c said he did not, and x, z ratio, please programmed to identifyA list of three teams racing.
Platform: |
Size: 1024 |
Author: laoying |
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